[Challenge] Flipping Cards

Question

You get a deck of cards with n cards. Then you turn every card, every second, every third, every fourth and so on until you turn the n-th card. The question is how many cards are then face-up? I give you an example of a deck with 4 cards. 0 represents hidden and 1 means open
0: 0 0 0 0
1: 1 1 1 1
2: 1 0 1 0
3: 1 0 0 0
4: 1 0 0 1
So the answer for n = 4 would be two. I now challenge you to write a code to solve this puzzle for a general n. You can also solve it mathematicaly annd you will get a much easier..

Answer 1

0)0000
1)1111
2)1010 //every 2nd
3)1000 //every 3rd
4)1001 //every 4th
//hope it makes sense to you ☺

//& by following it , here is my try
https://code.sololearn.com/cE8KuXITKBmx/?ref=app

Answer 2

Your example does not make sense
should 3 not rather be
3:1 0 0 0
then 4
4:1 0 0 1

Answer 3

https://code.sololearn.com/cdeL810a7V12/?ref=app

Answer 4

Enter amount of cards when asked

https://code.sololearn.com/c5hEV3XP5c28

Answer 5

Python :
n cards --> int(n**0.5) face-up

https://code.sololearn.com/cQijKOtyB2Fe/#py

Answer 6

hmmmmm
column c is flipped if it is n times row r

So 0 or 1 gives answer, if the count of devisors up to n id odd or even.
So far my first thoughts.

Could be wrong

Answer 7

Here is my answer with interpretation

https://code.sololearn.com/cABg86JUA0zU

Answer 8

https://code.sololearn.com/cRlgXTs0tEw6/?ref=app

Answer 9

0:0000
1:1111
2:1010
3:1000
4:1001
it should be like this!

Answer 10

how do we decide number of flips? is it deck size+1?
i.e. In example given above deck is of 4 cards and cards are flipped 5 times

Answer 11

What input should be given by user ?
Just number of cards or cards and flips?

Answer 12

.. and faster code.

I will update this post in 24 hours with my solution and explanations plus a mathematical proof.

Good luck!
[Post character limitations]

Answer 13

@code learner user input is deck size

Answer 14

I think the easy way is to determine the suare root of the number of cards, but I made a nice little code for further development, for example find out the face-up cards turn-by-turn.
https://code.sololearn.com/cLhAFc6dBj6A/#java