Hello could someone answer my Q for the code below:

Question

int main() {

int v1=5;
int v2=15;
int*p1;
int*p2;

p1=&v1;
p2=&v2;

*p1=10;
*p2=*p1;
p1=p2;
*p1=20;
cout<<"1st v is "<<v1<<endl;
cout<<"2nd v is "<<v2<<endl;

i just cant get why (v2)'s value will be 20 while we changed *p1 to 20 ??

thanks

Answer 1

it assigns p2 address to p1 since both are ptrs. So when given value 20 it assigns it to v2 which is address of p2

Answer 2

@Michael thank you but how about the role of
p1=p2 here?

Answer 3

@Michael thank you alot ,its clear now

Answer 4

*p2=*p1 -assigns ptr p1 value to p2 which is using address of v2