F&A Diskussionen
Why doesn't my << overloader work? And I am having problems understanding how to use std::async in C++.
-2 Stimmen
1 Antwort
How to correctly overload the << operator with seperate bodies for fstream and ostream ?
3 Stimmen
1 Antwort
Rearrange the code blocks to form a valid C++ program: #include <iostream> using namespace std; int main() { cout << "Awesome!
-2 Stimmen
3 Antworten
WY I get a rundum number from memory when I run this code
#include <iostream>
using namespace std;
int main ()
{
int array [5];
for (int x = 0; x < 5; x++) {
array [x] = 42;
cout << x << ': ' << array [x] << endl;
}
return 0;
}
if I replace ': ' with ": " every thing works well.
0 Stimmen
2 AntwortenCan someone pls explain what does this operator " << " and " >> "does with example?
0 Stimmen
2 Antworten
Can you code multiplication with only LOGICAL operations like & , ^ , | , << , >> but, without + or - or * or /
-4 Stimmen
16 Antworten
So i wanted to make a calculator so i did int << a = 5; int << b = 10; int sum a + b = 15; but it didnt work
0 Stimmen
1 Antwort
Even though I know the cause of error,but I don't know,why the __cout << "hii"__ line don't work?
0 Stimmen
2 Antworten
What's the difference between : {cout << x*2 ;} and {return x*2;} in a function?
0 Stimmen
2 Antworten
Can I put a string in "" and a variable by using cout << at the same time, or it should be separated?
1 Stimme
6 Antworten
If i am not wrong then cout <<"sum"; just Prints the word "Sum" while cout << sum; prints its value.
2 Stimmen
5 Antworten
Thanks to the lack of parenthesis and curly braces, the code is always much clearer and more readable than C or C++ code!
Example: C++ vs Python
if (x>0)
{ std::cout << "x is positive."
<< std::endl; }
if x>0:
print("x is positive.")
#Python4president
1 Stimme
6 Antworten
How do we arrive at 26 as answer here?
int a = 10;
int b = 13;
int *p1= &a;
int *p2= &a;
*p1 = b;
cout << (*p1) + (*p2);
7 Stimmen
6 Antworten
#include <iostream>
using namespace std;
int main() {
int x; int i=3;
x=++i + i++;
cout << x;
return 0;
}
3 Stimmen
3 Antworten
Hi guys, maybe this was already asked and answered but I could not find it... so here is my question:
0 Stimmen
2 Antworten
#include
using std::cout;
int main()
{
int i=0;
ย ย ย cout << (i=0? 1:2? 3:4);
ย ย return 0;
ย ย }
-3 Stimmen
3 Antworten
Cout__x
0 Stimmen
2 Antworten
#include <stdio.h> void main() { int x = 1, z = 3; int y = x << 3; printf(" %d\n", y); }
0 Stimmen
3 Antworten
Why does the output of int a = 100;
a = 50;
cout << a; come out with 50 instead of 100?
1 Stimme
5 Antworten
int a =10
int b = 2
a*=b
cout << a/ ++b
What is the output? And how do you derive it? Appreciate the help! Thanks!
0 Stimmen
9 Antworten
{
int a = 100;
a = 50;
cout << a;
return 0;
} Why the output is 50 as the value of a is 100 & 50
0 Stimmen
7 Antworten
int main()
{
int num = 1;
int number;
int total = 0;
while (num <= 5) {
cin >> number;
total += number;
num++;
}
cout << total << endl;
return 0;
}
i neeed a very simple discussion please about the loop i don't understand anything
1 Stimme
3 Antworten
#include <iostream>
using namespace std;
void test(int*, int*);
int main() {
int a = 5, b = 5;
cout << "Before changing:" <
-1 Stimme
2 Antworten
int i = 0;
OS obj;
while (obj.importaddr(i) != NULL)
{
if (obj.importname(i) != "Mac")
{
cout << "Is favo
0 Stimmen
2 Antworten
what is the output of this ?with explanation please.. int x=2 , y=3 , z=0 ; z=(x++)*(x++)+(++y)*(++y) ; cout << z ;
-2 Stimmen
3 Antworten
i want to make my code as neat as possible. This C++ teaches you.
if (A<B) {
cout << "Correct";
}
can i actually do, if (A<B)
{
cout << "Correct";
}
where my { put at below shouldent it be like this? and neater?
Sorry for bad english.
1 Stimme
2 Antworten
whats the difference in
<< "Hello world";
&
<<" Hello <<"world!";
both are shows display same " Hello world "
so, why this '<<' in between those ????
0 Stimmen
6 Antworten
What is the output of this code?
int arr[] = {2, 4, 6};
int x = (*arr + 1) * (*(arr + 1));
cout << x;
1 Stimme
1 Antwort
what is tjis code problem!
#include <iostream>
using namespace std;
int main()
{
int b = 5;
int arr[b] = {11, 35, 62, 555, 989};
int sum = 0;
for (int x = 0; x < 5; x++) {
sum += arr[x];
}
cout << sum << endl;
return 0;
}
I cannot make an array using int variable in order to define array's element number!?
1 Stimme
7 Antworten
#include <constream.h>
int main ()
{
int x = 10, y = 3, z;
for (z= 0; z < x;)
z = z++ +y;
cout <<"\n" << z;
return 0;
}
0 Stimmen
3 Antworten
Why we not use "" at the end of program to print enything means in this program they use cout << a .. they dont use"" so why...?
0 Stimmen
2 Antworten
int num = 1;
int number;
int total = 0;
while (num <= 5) {
cin >> number;
total += number;
num++;
}
cout << tota
0 Stimmen
2 Antworten
Plz answer?
1 Stimme
2 Antworten
Heute heiร
Web Development
3 Votes
Cybersecurity techies
4 Votes
Please complete this code.
0 Votes
What's wrong with code?
0 Votes
Please answer.
0 Votes
Introduction of html
0 Votes
Money Back
0 Votes