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Why are the output of this bonch of code like this?

numbers = [1, 2, 9, 8, 6] for i in range(0, 5): if i % 2 == 0: print(numbers[i]) ____________________ output: 1 9 6 I'd like to know why output is not 2, 8, 6 because reminders for these digits is zero. I can not understand how 1, 9 and 6 have reminder of zero while they divided to 2, So: 1 % 2 = 1 9 % 2 = 1 6 % 2 = 0 Right? Thanks all for your support and clear answer. I'm new in learning Python

3rd Nov 2023, 5:19 AM
Mahdi2211
Mahdi2211 - avatar
11 Antworten
+ 7
Mahdi Zabihi The i is from range, not the list. It will be the index, not the number in the list. your if should be if numbers[i]%2 == 2: to get 2,8,6 I feel you are still in the c mentality when looping. your for loop should be for i in numbers: if i%2==0: print(i)
3rd Nov 2023, 5:41 AM
Bob_Li
Bob_Li - avatar
+ 7
Mahdi Zabihi , From your above code using for loop you are checking the position is divisible by 2 or not... So you are getting 1 9 6 as output... As your code is like this... For loop runs for values 0,1,2,3,4 ----->(These are ' i ' values) 1st ITERATION: 0%2=0 (so condition satisfied It will print ---> numbers [i] as per your code...so number[0] as ' i ' value is ' 0 ' in first iteration .... which gives the output ' 1 ') 2nd ITERATION: 1%2!=0 (so condition FAILED) 3rd ITERATION: 2%2=0 (so condition satisfied It will print ---> numbers [i] as per your code...so number[2] as ' i ' value is ' 2 ' in THIRD iteration .... which gives the output ' 9 ') 4th ITERATION: 3%2!=0 (so condition FAILED) 5th ITERATION: 4%2=0 (so condition satisfied It will print ---> numbers [i] as per your code...so number[4] as ' i ' value is ' 4 ' in FIFTH iteration .... which gives the output ' 6 ')
3rd Nov 2023, 6:22 AM
Riya
Riya - avatar
+ 6
And if you need 2,8,6 as output means you have to modify the code as Bob_Li said...
3rd Nov 2023, 6:28 AM
Riya
Riya - avatar
+ 5
It is a shorten Riya's explanation. numbers = [1, 2, 9, 8, 6] for i in range(0, 5): # for i in range(5): if i % 2 == 0: print(number[i]) The results: i = 0 >> 0 % 2 = 0 >> 0 is equal to 0, print(number[0]) >> 1, next i; i = 1 >> 1 % 2 = 1 >> 1 is not equal to 0, next i; i = 2 >> 2 % 2 = 0 >> 0 is equal to 0, print(number[2]) >> 9, next i; i = 3 >> 3 % 2 = 1 >> 1 is not equal to 0, next i; i = 4 >> 4 % 2 = 0 >> 0 is equal to 0, print(number[4]) >> 6, end of loop It prints 1, 9, 6 With Bob_Li's code: for i in numbers: if i % 2 == 0: print(i) The result: i = 1 >> 1 % 2 = 1 >> 1 is not equal to 0, next i; i = 2 >> 2 % 2 = 0 >> 0 is equal to 0, print(2) >> 2, next i; i = 9 >> 9 % 2 = 1 >> 1 is not equal to 0, next i; i = 8 >> 8 % 2 = 0 >> 0 is equal to 0, print(8) >> 8, next i; i = 6 >> 6 % 2 = 0 >> 0 is equal to 0, print(6) >> 6, end of loop It prints 2, 8, 6
3rd Nov 2023, 6:47 AM
Wong Hei Ming
Wong Hei Ming - avatar
+ 4
for i in range(0, 5) will produce 0, 1, 2, 3, 4. Actually range(0, 5) can be shorten to range(5). Unless you want to specify the starting number, such as range(3, 5), which produces 3 and 4. If you want to loop through a list, just as Bob_Li said, for i in numbers.
3rd Nov 2023, 6:13 AM
Wong Hei Ming
Wong Hei Ming - avatar
+ 3
Thanks all guys😊🙏. I leant not only the code itself but more by ur gratful support.
4th Nov 2023, 6:13 AM
Mahdi2211
Mahdi2211 - avatar
+ 1
Bob_Li if numbers[i] % 2 == 0 ;)
3rd Nov 2023, 7:16 PM
Denise Roßberg
Denise Roßberg - avatar
+ 1
First of all... i has no remainder when it is 0 or 2 or 4 0%2=0 2%2=0 4%2=0 ...and then it prints the numbers from the list that has index 0, 2, 4 That's it.
3rd Nov 2023, 9:26 PM
Jan
Jan - avatar
+ 1
It seems there might be a misunderstanding. The output you provided is actually correct based on the code you provided. In the code you posted, you have a list of numbers `[1, 2, 9, 8, 6]`. The loop `for i in range(0, 5)` iterates over the indices `0, 1, 2, 3, 4`. When `i` is `0`, `numbers[i]` refers to the first element of the list, which is `1`. Since `1 % 2` is `1`, the condition `if i % 2 == 0` evaluates to `True` and `1` is printed. When `i` is `2`, `numbers[i]` refers to the third element of the list, which is `9`. Since `9 % 2` is `1`, the condition `if i % 2 == 0` evaluates to `True` and `9` is printed. When `i` is `4`, `numbers[i]` refers to the fifth element of the list, which is `6`. Since `6 % 2` is `0`, the condition `if i % 2 == 0` evaluates to `True` and `6` is printed. So the output is indeed `1, 9, 6`, which is consistent with the code you provided. If you expected the output to be `2, 8, 6`, then there might be a misunderstanding in your logic or an error in the code that you're using
4th Nov 2023, 12:07 PM
রহস্যময়— পৃথিবী
রহস্যময়— পৃথিবী - avatar
0
রহস্যময়— পৃথিবী I see you replied to lots of questions in a short time. However this is a place to learn coding, please don't give a ready made code easily, ok? Give some hints or advice so they can learn by themselves.
4th Nov 2023, 1:21 PM
Wong Hei Ming
Wong Hei Ming - avatar
0
🙏
31st Dec 2023, 2:01 PM
Mahdi2211
Mahdi2211 - avatar