C++ round integer UP to the next multiple of 10 | SoloLearn: Learn to code for FREE!

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C++ round integer UP to the next multiple of 10

It's embarrassing but although there are so many related articles out there, I just don't get it. Let's say that I have int numbersSum. If it is 41, I want to get an int of 50 if it is 67 I want to get an int of 70 Only round up to the next multiple of 10 and store that value in an int variable! I tried ceil but it won't do it. Any suggestions? Thanks in advance! 🍺 PS: Rookie here 😊

12/2/2017 5:30:51 PM

Dimitris Petrakis

3 Answers

New Answer

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@kurwius Haaaa That's awesome! ok other one #include <stdio.h> #include <math.h> int main(){ printf("%f",ceil(67.0/10)*10); return 0; }

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worked great! thank you so much, guys! I used your code @Very_Hard ! 😁