char b = 'a' + 2;
System.out.print(b);
I am facing issue while getting correct answer for this.
people are giving varying answers and contradicting to the correct one which is provided by sololearn.
Please help me with this
You're getting that because it's the ASCII value of the char.
char is actually an integer type. It stores the 16-bit Unicode integer value of the character in question.
You can look at something like http://asciitable.com to see the different values for different characters.
alijany already said it, it is because a char (eg. 'a') instead of a string (eg "a") has a fix ASCII value. by adding a numeric value to it you get the next ASCII value in the line ... so bei adding 2 to the value of a you get c.
you can google ascii table to see some examples and play around with it
here is somthing to work with.^^
public class Program
{
public static void main(String[] args) {
int a = 'a';
char b = 98;
System.out.println(a); // prints value of 'a'
System.out.println(b); // prints char of value 98
}
}
