C++ data types

Question

In the following code, whether I use a float or double, I get the same number as a result. Shouldn't the double, display a number with more digits after the decimal point???? I used for example the number 3.111111 with six "1s" and it still outputs the number 3.11111 with five "1s", as the float did...
#include <iostream>
using namespace std;
int main()
{
double a;
cin >> a;
cout << a;
}

Answer 1

You need to use setprecision() on the cout object.
http://www.cplusplus.com/reference/iomanip/setprecision/
ex: std::setprecision(numberofdigits);

Answer 2

-A detailed tutorial on data types
https://www.tutorialspoint.com/cplusplus/cpp_data_types.htm

Answer 3

Calculations in double are more precise but to output the result with a given number of digits you need to precise it....

Answer 4

Yes. You need to format the output.

Answer 5

Each Data type in C++ such a number types int, double , float, long double, have ranges.

Answer 6

double will not display extra zeros
eg 14.0 - float would display the zero though

Answer 7

if you want a variable to have a certain amount of digits used the right data type for the job

Answer 8

@Christos
if you give the value long (long doub) 12.0001
that number will be displayed
if you give 12.000
double will ignore the zeros and output 12

Answer 9

Here is a example
https://code.sololearn.com/cBga5IERN57L/?ref=app

Answer 10

My mistake that code takes the remainer of what is not covered in a data type.
max ranger if no value for a range

Answer 11

@manual
Actually the same happens with float

Answer 12

So this should be used only on the cout object? If i use the input as a value for the rest of the program, for calculations etc., It would use the number initially given??

Answer 13

@Manual
That's the reason I used the double; to increase the range...

Answer 14

@Karl T.
So the program will use the given value but can't print it without the precision???