What the answer

Drag and drop from the options below to add 'z' to the end of the list and print the list's length. list. ('z') print( ) ) insert len append (list) index. What go in the gap

list.append ('z') print( len (list) )

the ans is if "z" in letters: print("Yes")

Thanks to Makhan

Fill in the blanks to create a stack of integers and push 11, 42, and 15 to it. Print "yes" if the stack contains 42. Stack<int> st = new Stack< int >(); st .Push(11); st.Push(42); st.Push(15); (st.Contains(42)) { Console.WriteLine("yes"); } What is the answer?

list.append ('z') print( len (list) )

If"z"in

Fill in the blanks to create a set, add the letter "z" to it, and print its length. nums = { "a", "b", "c", "d" } nums. add ("z") print( len (nums))

help me Fill in the blanks to create a stack of integers and push 11, 42, and 15 to it. Print "yes" if the stack contains 42. Stack<int> st = new Stack< int >(); st .Push(11); st.Push(42); st.Push(15); (st.Contains(42)) { Console.WriteLine("yes"); }

void print(int n) { if (n < 0) return; printf("%d", n); print(n - 1); }

Заполните пробелы, чтобы напечатать "да", если список содержит 'z': буквы = ['A', 'b', 'z'] "Зет" буквы: печать ("да")

letters = ['a', 'b', 'z'] if "z" in letters: print("Yes")

letters = ['a', 'b', 'c'] for l in letters : print(l)

can you please try the following letters = ['a', 'b', 'z'] if "z" in letters: print("Yes")

The answer is if "z" in letters:

Fill in the blanks to create a set, add the letter "z" to it, and print its length. nums = { "a", "b", "c", "d" } nums. add ("z") print( len (nums))

: )

la respuesta es if y en el otro recuadro va in

letters=['a','b','z'] if "z" in letters: print("yes")