What the answer

Question

Fill in the blanks to print "Yes" if the list contains 'z':
what's the answer
letters = ['a', 'b', 'z']
_ "z" _
letters:
print("Yes")

Answer 1

list.append ('z')
print( len (list) )

Answer 2

the ans is
if "z" in letters:
print("Yes")

Answer 3

Fill in the blanks to create a set, add the letter "z" to it, and print its length.
nums =
{
"a", "b", "c", "d"
}
nums.
add
("z")
print(
len
(nums))

Answer 4

If"z"in

Answer 5

Fill in the blanks to create a stack of integers and push 11, 42, and 15 to it. Print "yes" if the stack contains 42.
Stack<int> st = new Stack<
int
>();
st
.Push(11);
st.Push(42);
st.Push(15);
(st.Contains(42)) {
Console.WriteLine("yes");
}
What is the answer?

Answer 6

Stack<int> st = new Stack<
int
>();
st
.Push(11);
st.Push(42);
st.Push(15);
if(st.Contains(42)) {
Console.WriteLine("yes");
}

Answer 7

Thanks to Makhan

Answer 8

la respuesta es if y en el otro recuadro va in

Answer 9

1. if
2. in

Answer 10

Drag and drop from the options below to add 'z' to the end of the list and print the list's length.
list. ('z')
print( ) )
insert len append (list) index.
What go in the gap

Answer 11

list.append ('z')
print( len (list) )

Answer 12

void print(int n) {
if (n < 0) return;
printf("%d", n);
print(n - 1);
}

Answer 13

Заполните пробелы, чтобы напечатать "да", если список содержит 'z': буквы = ['A', 'b', 'z']
"Зет"
буквы:
печать ("да")

Answer 14

letters = ['a', 'b', 'z']
if "z" in letters:
print("Yes")

Answer 15

letters = ['a', 'b', 'c']
for
l
in
letters
:
print(l)

Answer 16

can you please try the following
letters = ['a', 'b', 'z']
if
"z"
in
letters:
print("Yes")

Answer 17

The answer is
if "z" in letters:

Answer 18

Fill in the blanks to create a set, add the letter "z" to it, and print its length.
nums =
{
"a", "b", "c", "d"
}
nums.
add
("z")
print(
len
(nums))

Answer 19

: )