What the answer

Drag and drop from the options below to add 'z' to the end of the list and print the list's length. list. ('z') print( ) ) insert len append (list) index. What go in the gap

the ans is if "z" in letters: print("Yes")

list.append ('z') print( len (list) )

list.append ('z') print( len (list) )

Thanks to Makhan

Fill in the blanks to create a set, add the letter "z" to it, and print its length. nums = { "a", "b", "c", "d" } nums. add ("z") print( len (nums))

void print(int n) { if (n < 0) return; printf("%d", n); print(n - 1); }

Заполните пробелы, чтобы напечатать "да", если список содержит 'z': буквы = ['A', 'b', 'z'] "Зет" буквы: печать ("да")

letters = ['a', 'b', 'z'] if "z" in letters: print("Yes")

letters = ['a', 'b', 'c'] for l in letters : print(l)

can you please try the following letters = ['a', 'b', 'z'] if "z" in letters: print("Yes")

The answer is if "z" in letters:

The answer is if "z" in letters:

If"z"in

Fill in the blanks to create a set, add the letter "z" to it, and print its length. nums = { "a", "b", "c", "d" } nums. add ("z") print( len (nums))

: )

if and in

letters = ['a', 'b', 'z'] if "z" in letters: print("Yes")

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