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Fill in the blanks to print "Yes" if the list contains 'z': what's the answer letters = ['a', 'b', 'z'] _ "z" _ letters: print("Yes")

5/10/2017 3:25:46 AM

Bianca

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Drag and drop from the options below to add 'z' to the end of the list and print the list's length. list. ('z') print( ) ) insert len append (list) index. What go in the gap

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list.append ('z') print( len (list) )

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the ans is if "z" in letters: print("Yes")

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Thanks to Makhan

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Fill in the blanks to create a stack of integers and push 11, 42, and 15 to it. Print "yes" if the stack contains 42. Stack<int> st = new Stack< int >(); st .Push(11); st.Push(42); st.Push(15); (st.Contains(42)) { Console.WriteLine("yes"); } What is the answer?

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list.append ('z') print( len (list) )

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If"z"in

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Fill in the blanks to create a set, add the letter "z" to it, and print its length. nums = { "a", "b", "c", "d" } nums. add ("z") print( len (nums))

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help me Fill in the blanks to create a stack of integers and push 11, 42, and 15 to it. Print "yes" if the stack contains 42. Stack<int> st = new Stack< int >(); st .Push(11); st.Push(42); st.Push(15); (st.Contains(42)) { Console.WriteLine("yes"); }

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void print(int n) { if (n < 0) return; printf("%d", n); print(n - 1); }

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Заполните пробелы, чтобы напечатать "да", если список содержит 'z': буквы = ['A', 'b', 'z'] "Зет" буквы: печать ("да")

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letters = ['a', 'b', 'z'] if "z" in letters: print("Yes")

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letters = ['a', 'b', 'c'] for l in letters : print(l)

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can you please try the following letters = ['a', 'b', 'z'] if "z" in letters: print("Yes")

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The answer is if "z" in letters:

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Fill in the blanks to create a set, add the letter "z" to it, and print its length. nums = { "a", "b", "c", "d" } nums. add ("z") print( len (nums))

0

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la respuesta es if y en el otro recuadro va in

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letters=['a','b','z'] if "z" in letters: print("yes")