how do i get the value inside this list???

Question

I want to get the "anoTrabalho", how do I get it?
d = {
"Pedro": {"salario": 800, "anoTrabalho": 3},
"Ana": {"salario": 1200, "anoTrabalho": 2},
"Luis": {"salario": 200, "anoTrabalho": 0},
"Joao": {"salario": 900, "anoTrabalho": 4}
}

Answer 1

sunshine ,
we can also get the reqired value from the key *anoTrabalho* without using a loop:
name = input()
print(d[name]['anoTrabalho']) # using bracket notation. this will crash if the input name is not a key in the dict.
# or:
print(d.get(name, {}).get('anoTrabalho')) # using <dictionary>.get(): in case of the key could not be found, there is a workaround to return *None*.

Answer 2

d.items() contains key-value pairs of string (name) and a dictionary (salary & year of work). So we can refer the desired dictionary item using the already known key name ("anoTrabalho")
for k, v in d.items():
print( k, v[ 'anoTrabalho' ] )
Mind that the key is case sensitive, must match exactly.
(Edit)
It's a nested dictionary BTW, not a `list`. If you don't mind, you can update the title of the post.

Answer 3

You have a nested dictionary, so you need to iterate through the keys of the first dictionary to get to the inside dictionary.
for name in d:
    print(d[name]["anoTrabalho"])
The "for name in d" will assign the key to variable 'name' on each iteration.
Then when printing, the d[name] will get you to the values of the first dictionary which is the nested dictionary. The second bracket ["anoTrabalho"] will provide the value for that key of the inner dictionary.

Answer 4

sunshine I could be wrong, but it could be because "worker" isn't in the variable "d".
Also, you should provide what programming language you're using this in.

Answer 5

you can convert the result of worker to a list and print the second item .
for k in d:
print( list( d.get(k) )[1])

Answer 6

this:
for worker in d:
print(d[worker]["anoTrabalho"])