#include<stdio.h> int main(){ printf("MY SIMPLE CALCULATOR"); printf("\nInstructions"); char name[50]; printf("\n Ent

What did you change?

Chike Chewakondi please show us your attempt. I gather this is a c code but you attempted to put your code in the title verses the description part of the question section of the thread.

Chike Chewakondi and BroFar , here's the right way to add code: 1. Enter the code in Code Playground 2. Save it as public 3. In the question description, tap "+" button 4. Select code If you already posted the question, just edit it. Also, use tags to inform the language. "please" and "really" give absolutely no information.

https://code.sololearn.com/cbn5meiBk8IV/?ref=app

Instead of using multiple if else use switch case statements

Bro, you can use these methods for clear keyboard buffer in c :- 1. scanf(" %c",&op); 2. fflush(stdin); scanf("%c,&op);

Really sorry for that, thanks for the concern

I have difficulties to post that

Can you grab a copy and post it here in the thread so we can see how to help you? Chike Chewakondi

#include<stdio.h> int main(){ printf("MY SIMPLE CALCULATOR"); printf("\nInstructions"); char name[50]; printf("\n Enter your name:"); gets(name); printf("\n\n %s,To perform an operation,Enter 1""\n -and,To perform a summation,""Enter 2:",name); int option; scanf("\n%d",&option); if(option==1){ printf("\n You have chosen option=%d,%s",option,name); printf("\n So,To perform an operation for only two numbers,Enter one of the following operators"); char operator; printf("\n [+,-,*,/]"); printf("\n Operator:"); scanf("%c", &operator); double num1,num2; printf ("\n %s,Please enter first number value:",name); scanf("%lf",&num1); printf ("\n and second number value:"); scanf("%lf",&num2); double result; switch(operator){ case '+': result=num1+num2; printf("\n%s, your result is %.1lf", name,result); break; case '-': result=num1-num2; printf("\n%s, your result is %.1lf",name,result); break; case '*': resul

Looks like you need to have knowledge of all inputs ahead of time Chike Chewakondi and enter them in the beginning. https://code.sololearn.com/cbn5meiBk8IV/?ref=app

So how do l go about

I thought it was just exactly there we had to input a value, but it always seemed to skip that line

Chike Chewakondi first error change gets to scanf("%s", &name); 1 error down option 1 and option 2 seem to be fine it doesn't appear to be picking up the operator num1 and num2 appear to be floats try it with int as %d vs %lf not sure if you have other inputs / scanf(s) I missed.

What if the inputted num values are decimal points

It's still skipping the operator read part, what do you propose sir

Chike Chewakondi here is mine from 3 years ago https://code.sololearn.com/cjxo10O7D1t0/?ref=app

Thanks for the tip but if you remove the part of my code which operates, it works well but when you insert that in another conditional, the problem starts

#include<stdio.h> int main() { printf("MY SIMPLE CALCULATOR"); printf("\n To perform an operation" "\n Enter one of the following operators"); printf("\n [+,-,*,/]"); char operator; printf("\n Operator:"); scanf("%c",&operator); double num1,num2; printf ("\n Enter first number value:"); scanf("%lf",&num1); printf("Num 1= %lf",num1); printf ("\n Enter second number value:"); scanf("%lf",&num2); printf("\nNum 2= d%",num1); double result; printf("\n The result is %lf",result); switch(operator){ case '+': result=num1+num2; printf("\n The result is %lf",result); break; case '-': result=num1-num2; printf("\n The result is %lf",result); break; case '*': result=num1*num2; printf("\n The result is %lf",result); break; case '/': result=num1/num2; printf("\n The result is %lf",result); break; default: printf("Invalid input"); } return 0; } As this

Emerson Prado, thanks for the tip, could you give some concerning my code