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How to make program to print 1 to 1000 Armstrong number in java

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5/2/2022 6:53:50 AM

Ranjna Gupta

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Ranjna Gupta Do you know the logic of Armstrong Number? If yes then you can do for 1000 numbers using loop Show attempts. Armstrong Number means: number = sum of cubes of each digit eg.- 123 = 1**3 + 2**3 + 3**3 if LHS = RHS then Armstrong Number otherwise not

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# Input a three digit number.Say 'n' n = int(input("Enter a three digit number. ")) # logic is # Let's say user entered 321. # If 3**3 + 2**3 + 1**3 (Summation of cube of all digits of the given number) == Given Number # Then we can say it is a Armstrong number else not. summation = 0 ans = n while n>0: digit = n%10 summation += digit**3 n = int(n/10) if summation == ans: print(True) else: print(False) # Hope you got the crux :) # Code in python (So, you convert it into Java accordingly)

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Here is a java method to check whether a number is Armstrong number or not. /** * This method return true if num is armstrong number otherwise returns * false */ public static boolean isArmstrongNumber(int num) { int sum = 0, rightDigit, temp; temp = num; while (temp != 0) { rightDigit = temp % 10; sum = sum + (rightDigit * rightDigit * rightDigit); temp = temp / 10; } /* * Check if sum is equal to N, then N is a armstrong number otherwise * not an armstrong number */ if (sum == num) { // N is armstrong number return true; } else { // N is not an armstrong number return false; } } I found the full program to print armstrong number here https://www.techcrashcourse.com/2017/03/java-program-print-armstrong-numbers-between-1-to-N.html