Help me!!! It's very difficult the exersice 20.5, please of python. | Sololearn: Learn to code for FREE!

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Help me!!! It's very difficult the exersice 20.5, please of python.

This is my code: number = input() if number == "1": print (int(number)*3) elif number == "2": print (int(number)*2) elif number == "0": print (int(number)*0) else: print (int(number)*3)

1/16/2022 4:08:55 PM

Jefferson Jesus Beleño Suarez

8 Answers

New Answer

+4

Jefferson Jesus Beleño Suarez number = int(input()) if number%2==0: print (number*2) elif number%2==1: print (number*3) else: print (0) You need to use int(input())

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Krishni okay, sorry, if my comment confused you!

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You only check the numbers 1 and 2 – but you need to test if the input is odd or even.

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Wow! Thank you very much Krishni

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Lisa By finding the reminder when divided by 2, we can come to know if the input is odd or even

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Lisa ok But I thought it was a question 😅

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Krishni my comment is a reply to the OP's question

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You can convert the user input to integer