C++ Ballpark order challenge

Question

Hello im trying to solve the Ballpark Orders challenge in c++ and for some reason, only first item gets right amount when calculation total sum. Here is the code.
#include <iostream>
#include <sstream>
using namespace std;
int main() {
string burger = "Cheeseburger";
string nachos = "Nachos";
string pizza = "Pizza";
string water = "Water";
string coke = "Coke";
int sum = 0;
string order;
cin >> order;
string arr[4];
int i = 0;
stringstream ssin(order);
while (ssin.good() && i < 4){
ssin >> arr[i];
++i;
}
for (int j = 0; j < 4; j++){
cout << sum;
if (arr[j] == nachos || arr[j] == pizza) {
sum += 6;
} else if (arr[j] == burger ) {
sum += 10;
} else if (arr[j] == water ){
sum += 4;
} else if (arr[j] == coke ){
sum += 5;
} else {
sum += 5;
}
}
double tax = sum * 0.07;
cout << sum + tax;
}

Answer 1

Replace
cin >> order;
by
getline(cin, order);
to fix the issue, as std::cin is designed to stop extracting characters when encountering any kind of whitespace, while getline() by default only stops reading at the newline character.

Answer 2

Thanks for the suggestion. It indeed work and replacing std cin with get line did the trick. Thanks.

Answer 3

#include <iostream>
using namespace std;
int main() {
string order[5];
cin >> order[0] >> order[1] >> order[2] >> order[3] ;
string item[]={"Nachos", "Pizza", "Cheeseburger", "Water", "Coke"};
int sum = 0;
for (int x=0; x<4; x++){
if (order[x] == item[0]){
sum += 6 ;
}else if (order[x] == item[1]){
sum += 6 ;
}else if (order[x] == item[2]){
sum += 10 ;
}else if (order[x] == item[3]){
sum += 4 ;
}else if (order[x] == item[4]){
sum += 5 ;
}else sum += 5 ;
}
cout << sum + sum * .07 ;
return 0;
}
https://code.sololearn.com/cf5K1k91UFf5/?ref=app

Answer 4

Hi
I am solving this problem but ther is a bug in my code that I am not getting. So, please help me to find out for this.
#include <stdio.h>
#include <string.h>
int main(){
char str[200] = {0}, s[50]={0};
float ttl=0;
int mrp=0, cnt =0;
scanf("%[^\n]%*c", str);
for(int i=0, j=0; strlen(str)>=i; i++)
{
s[j++]=str[i];
if((str[i]==' ') || strlen(str)==i)
{
s[j-1] = '\0';
j = 0;
cnt++;
if(strcmp("Nacho", s) == 0 || strcmp("Pizza", s) == 0) mrp =6;
else if(strcmp("Cheeseburger", s) == 0) mrp =10;
else if(strcmp("Water", s) == 0) mrp =4;
else if(strcmp("Coke", s) == 0) mrp =5;
else mrp =5;
ttl += (float) mrp;
}
}
if(cnt<4) ttl += (4-cnt)*5.0;
ttl += (0.07*ttl);
printf("%.2f\n", ttl);
return 0;
}

Answer 5

So lets say Water is first Word ina string. Sum variable gets the correct amount of 4 but then if second Word is again water, it Will get 5 now, according to else condition. And Like this, its with every item, first is always correct then others are not. I tried to look hard for solution but failed to do so for quite some time now. Thanks l.

Answer 6

The only way that I found to solve this challange was to create a variable named braker, containing a zero, and each time an order fit one of my if statements I turn the value of the variable braker to one and then to the end of my loop I have an if statement that require the braker to be at zero to work... And everytime the loop make a new turn the braker turn back to zero.
#include <iostream>
using namespace std;
int main() {
unsigned short bill;
string words;
for(int roll=0;roll<4;roll++){
cin >> words;
int braker = 0;
if(words == "Water"){
bill+=4;
braker = 1;
}
if(words == "Nachos"||words == "Pizza"){
bill+=6;
braker = 1;
}
if(words == "Cheeseburger"){
bill+=10;
braker = 1;
}
if(braker == 0){
bill+=5;
}
}
cout << bill+bill*0.07 << endl;
return 0;
}
If anyone know a better way to solve this let me know...