java basics

Question

hello, when I try to get user input I have issue when I enter integer and string value using nextLine() method .so how I overcome this problem
(sorry if iam asking a silly question)

Answer 1

Could you please put your code in a script on playground and link it here So we can check on your code?

Without seeing the code it us hard to tell what is going on

Answer 2

nextLine() Reads Strings
for Numerical input : nextInt(); , nextDouble(); , nextFloat();
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
double d = scanner.nextDouble();

Answer 3

Not silly at all

So in order to get a value using nextLine() method

Scanner s= new Scanner(System.in); // Create a Scanner called s(you can name it whatever you want though) System.out.println("Enter your name");
//here you are telling the user what input are you asking for
String name = s.nextLine(); // Read user input System.out.println("name: " + name); // Output user input

there are diffrent methods that you can practice too like nextBoolean() ,nextLong(), read about them so that you can accumulate knowledge

Answer 4

nextLine() reads entire line as input but where as nextInt() reads an integer next in console input and stay in same line.
So in combination:
nextInt(); nextLine(); input must in same line as ex: 12 string_input
Ex: input:
12
String_input //this will not read by nextLine(), because it's already read \n carriage after 12.
To overcome this: read similar datatypes in sequence,then add a empty nextLine(); or read all inputs by nextLine() and convert to appropriate compatible needed types....