Can someone tell me whats wrog with this code? | Sololearn: Learn to code for FREE!

0

# Can someone tell me whats wrog with this code?

Here's my code #This program's purpose is to tell if integers are distinct number = int(input("Enter a number")) for i in range(number): integer = int(input("Enter an integer :")) if integer != integer: print("The integers entered are distinct.") else: print("You entered repeated integers") can someone tell me why itsn't working? Even when I input different integers it still displays that I entered repeated integers.

10/25/2021 2:41:14 PM

Rim Lamghari

+4

Okay.... at the beginning numbers = [ ] Now append each input to the list. Now tatatata🥳🥳🥳 the trick how to find out if there are duplicates in the list: If len(set(numbers)) == len(numbers): #no duplicates Give it a try and ask again if u struggle.

+3

integer != integer Is impossible as 3 != 3 Do you know lists? It would help.

+3

nums=[] number = int(input("Enter a number")) for i in range(number): nums.append(int(input("Enter an integer :"))) if len(set(nums)) == number: print("The integers entered are distinct.") else: print("You entered repeated integers")

+1

I tried list but didn't know how to use them in this case

+1

It didn't work

+1

can you write for me to see?

+1

Using lists are definitely easier. You append all of the integers to a list. And then you run a loop through the list to check if the elements are distinct. This is a sample code: N=int(input("Enter a no:")) Lst=[] for i in range(N):   x=int(input("enter an integer:"))   Lst.append(x) for i in range(len(Lst)):     if Lst[i]==Lst[i-1]:        print("The integers are not distinct") else:     print("Distinct") Hope it helps.

0

That number need to have diferent variable name

0

thank you I figured out

-1

U didn't declare i