Can someone tell me whats wrog with this code?

Question

Here's my code
#This program's purpose is to tell if integers are distinct

number = int(input("Enter a number"))
for i in range(number):
integer = int(input("Enter an integer :"))

if integer != integer:
print("The integers entered are distinct.")

else:
print("You entered repeated integers")

can someone tell me why itsn't working? Even when I input different integers it still displays that I entered repeated integers.

Answer 1

Okay....
at the beginning
numbers = [ ]
Now append each input to the list.

Now tatatata🥳🥳🥳 the trick how to find out if there are duplicates in the list:
If len(set(numbers)) == len(numbers):
#no duplicates

Give it a try and ask again if u struggle.

Answer 2

integer != integer
Is impossible as
3 != 3

Do you know lists?
It would help.

Answer 3

nums=[]
number = int(input("Enter a number"))
for i in range(number):
nums.append(int(input("Enter an integer :")))

if len(set(nums)) == number:
print("The integers entered are distinct.")

else:
print("You entered repeated integers")

Answer 4

I tried list but didn't know how to use them in this case

Answer 5

It didn't work

Answer 6

can you write for me to see?

Answer 7

Using lists are definitely easier. You append all of the integers to a list. And then you run a loop through the list to check if the elements are distinct.
This is a sample code:
N=int(input("Enter a no:"))
Lst=[]
for i in range(N):
  x=int(input("enter an integer:"))
  Lst.append(x)
for i in range(len(Lst)):
    if Lst[i]==Lst[i-1]:
       print("The integers are not distinct")
else:
    print("Distinct")

Hope it helps.

Answer 8

That number need to have diferent variable name

Answer 9

thank you I figured out

Answer 10

U didn't declare i