Is there a problem in line 2?

Question

lower, upper, special, digit = 0, 0, 0, 0
password = input(str)
if (len(password) >= 7):
for i in password:
if(word[0].isupper()):
upper += 1
if(i.islower()):
lower += 1
if(i.isdigit()):
digit += 2
if(i == '@'
or i == '

Answer 1

Yes, remove this 'str' to
password = input()

Answer 2

you can just use password = input()
If you do not set it to lets say an integer like int(input()) it will automatically assume it is a string. Hope this helps!

Answer 3

Yes, there must be also an other issue. But I'm not so fast 😉

Answer 4

Coding Cat
Task:
Write a program that takes in a string as input and evaluates it as a valid password. The password is valid if it has at a minimum 2 numbers, 2 of the following special characters ('!', '@', '#', '#x27;, '%', '&', '*'), and a length of at least 7 characters.
If the password passes the check, output 'Strong', else output 'Weak'.

Answer 5

There are many issues. I'm on work

Answer 6

Maybe this is better.
DON'T DO MORE AS YOU HAVE TO DO!
And for code coach, Do NOT make any outputs more as they ask for!
https://code.sololearn.com/ciT2skV07385/?ref=app

Answer 7

Now there are special characters missing. In the text above I see seven. But only four are checkt in your code.

Answer 8

Very nice. Gern geschehen.

Answer 9

Coding Cat
Thanks. I did it. The result must be "Strong" but now is "no Output"

Answer 10

Coding Cat thanks Coding Katze. What is wrong with this?
https://code.sololearn.com/cPHFaacz5f25/?ref=app

Answer 11

Idk. Some broken spaces maybe from copy and paste.
I've deleted this if sequence and have it rewritten.
https://code.sololearn.com/cST08FWLjqIS/?ref=app

Answer 12

And the digits are now missing
if(i.isdigit()):
digit += 1

Answer 13

Danke sehr. It worked
https://code.sololearn.com/cPHFaacz5f25/?ref=app