Can some one please help me to solve this one?

Question

We are going to write a program that will calculate the area of ​​a circle.
The area enclosed by a circle of radius r is πr², where π (pi) is the constant ratio of the circumference of any circle to its diameter, and r is the radius.
The given program declares a constant pi variable with a value of 3.14.
Complete the program to take the radius as input, then calculate and output the area of the circle.
Sample Input
5
Sample Output
78.5

Answer 1

Please show your attempt...So we can help you :)

Answer 2

Tim Tam follow these steps:
1. Take input into the variable radius, using
Console.ReadLine()
2. Create a variable, (suppose area for example.)
3. Calculate area of circle by the given formula:
area = pi * radius * radius;
5. Print the area using :
Console.WriteLine(area);
And still if you're unable to solve the challenge, kindly revisit on previous chapters.
Happy Coding :)

Answer 3

Tim Tam here you go..
https://code.sololearn.com/cVVXV2H2Jg8A/?ref=app

Answer 4

const double pi = 3.14;
double radius = Convert.ToDouble(Console.ReadLine());
double area = pi*radius*radius;
Console.WriteLine(area);

Answer 5

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace SoloLearn
{
class Program
{
static void Main(string[] args)
{
const double pi = 3.14;
double radius = Convert.ToDouble(Console.ReadLine()); // For all test cases
double area = pi*radius*radius;
Console.WriteLine(area);
}
}
}

Answer 6

Because we have a decimal (pi) so the result must be decimal.

Answer 7

Thank you

Answer 8

https://code.sololearn.com/cvHtMNlx0Kkt
double r = Convert.ToDouble(Console.ReadLine());
double a = Math.PI * Math.Pow(r, 2.0);
Console.WriteLine(Math.Round(a, 1));
// Keep learning & happy coding :D

Answer 9

Thank you so much guys😍😍😍

Answer 10

Hi SoloProg,
Because the method you did I haven't learned so I tried to combine you and Rupali together but still something wrong,
Can someone help me to fix it
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace SoloLearn
{
class Program
{
static void Main(string[] args)
{
const double pi = 3.14;
double radius;
radius = 5;
Convert.ToDouble(Console.ReadLine(area));
area = pi*radius*radius;
Console.WriteLine(area);
//your code goes here
}
}
}

Answer 11

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace SoloLearn
{
class Program
{
static void Main(string[] args)
{
const double pi = 3.14;
double radius;
//your code goes here
}
}
}

Answer 12

Yay I got it guys
Thank you so much,
Another thing is testcase number is done but in the test case number 2 still show the results of the test case number input 5 and out put 78.5,
Just want to ask how to separate 2 test case or I mean I can have another input for radius like radius = 6.4
Hope you guy understand what I am trying to say😅

Answer 13

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace SoloLearn
{
class Program
{
static void Main(string[] args)
{
const double pi = 3.14;
double radius = 5;
Convert.ToDouble(Console.ReadLine());
double area = pi*radius*radius;
Console.WriteLine(area);
//your code goes here
}
}
}
{
static void Main(string[] args)
{
const double pi = 3.14;
double radius = 6.4;
Convert.ToDouble(Console.ReadLine());
double area = pi*radius*radius;
Console.WriteLine(area);
//your code goes here
}
}
}

Answer 14

the Radius is not meant to be named twice and because you're radius is a while number it's not a double its a whole number meaning you should equal it to an int if you want to name your area variable a double do cause the answer will have a , after it meaning answer could be 2.2 example only.not answer hope it helps