 In Java, how do we make a type double round UP to the nearest integer? | Sololearn: Learn to code for FREE!

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# In Java, how do we make a type double round UP to the nearest integer?

a= (b/ c); If b is a double, (eg. 5.000053631), how would I be able to cast it to an integer type, with a value of 6 with and without the use of rounding methods, like ceil()? I would need this to work no matter what the value of b may be. 1.3 should round to 2, 12345.22222 should round to 12346, 5678.0987 should round to 5679, etc...

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double a = 5.00005361; int i = (int) Math.ceil(a); System.out.println(i);

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@Mohd Aadil, that's Python, Solus requires Java.

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@HrCoder, using a cast will not round up. Using a cast is similar to using Math.floor(), it always rounds down i.e. truncates everything after the decimal point.

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Without using Math.ceil, something like this could work: int ceil = (int) ((x > (int) x) ? x+1 : x); https://code.sololearn.com/cS4ygbflwW4T/?ref=app

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Martin Taylor casting a float number to integer number will round up for negative numbers and round down for positive numbers. Edit: it seems you have edited your answer

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Martin Taylor sorry for the wrong information

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double a=12345.2222; int s1=(int)Math.ceil(a); int s2=(int)Math.floor(a); int s3=(int)Math.round(a); //s1=12346 //s2 & s3 =12345

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Math.round(); function rounds to the nearest integer. Math.ceil(); function rounds to nearest higher integer Math.floor(); rounds to nearest lower integer I hope that my answer helps you...

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In order for you to able to call that back you’d have to add a math.round function)