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# Calculate SD :

# Statement : ''' players_heights = [180,172,178,185,190,195,192,200,210,190] The given code includes a list of heights for various basketball players. You need to calculate and output how many players are in the range of one standard deviation from the mean. '''

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variance = for_variance / N

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Aditya Nijave Where is attempts?

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A͢J - S͟o͟l͟o͟H͟e͟l͟p͟e͟r͟ players_heights = [180,172,178,185,190,195,192,200,210,190] sum_of_total_players_height = 0 for players_height in players_heights: sum_of_total_players_height += players_height N = len(players_heights) mean = sum_of_total_players_height / N for_variance = 0 for players_height in players_heights: as_required_fig = (players_height - mean)**2 for_variance += as_required_fig variance = for_variance / (N-1) SD = variance**0.5 for_range = [] lower_limit = mean - SD upper_limit = mean + SD for players_height in players_heights: if lower_limit <= players_height <= upper_limit: for_range.append(players_height) spread_out = len(for_range) print(f"{spread_out}")

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Aditya Nijave No need to write this much logic. You have already calculated mean, just filter list on that mean and get new list like this: list1 = [i > mean for i in players] #this will return a list of True, False print (sum(list1)) Note: You can directly get sum of list using sum function, no need to use loop