Spread Operator (JS)

Question

const object1 = {foo: "bar", x: 42};
const object2 = {foo: "baz", y: 5};
const merge = (...objects) => ({...objects});
let mergeObject = merge(object1, object2);
console.log(mergeObject);
let mergeObject1 = merge({}, object1, object2);
console.log(mergeObject1);
Can anyone kindly explain what is happening in the merge function or how is it working? This is the last example from spread operator section of JS course. Having a hard time over this example.
Playground link: https://code.sololearn.com/WA2177a20A21
Thanks in advance.

Answer 1

In the merge function whatever you pass, it will actually be passed as a single parameter and returning the all.
As you have used spread operator, you can pass as more as parameter you want. All parameters will be passed as a single one.