Pre-increment and Post-increment

Question

#include <stdio.h>
int main()
{
int a=2,b=3;
b=a++ + b--;
printf("\n%d %d : a b",a,b);
a=a-- + ++b;
printf("\n%d %d : a b",a,b);
b=++a + --b;
printf("\nFinal values of a and b are %d %d",a,b);
return 0;
}
Can anyone tell me the output of this code and please explain it to me! By solving on paper I have got a different value and the IDE shows the other. So by your answer, I can cross-check the mistake

Answer 1

Ujwal Sai Simha Y
b=2+3=5 post-incre/decre a=3 b=5
a=3+6=9 pre-incre for 'b' b=6 and a=9
b=10+5 pre-incre for 'a' a=10 , pre-decre for 'b' b=5
final a=10 b=15

Answer 2

@Thirt13n We get b=5 in the first condition and then will not be the post-decrement applied to it? I mean won't it be b=4 after post-decrement?

Answer 3

Ujwal Sai Simha Y
Increment/Decrement (++/--) has higher precedence than assignment (=) , first be will be decremented to 2 but after that it assigned with 5 , so b=5 !
Hope it will help you better !