why cout<<n prints 0 when I input other than integers, supposed to show something else?

Question

When I give input other than an integer i.e. char, string or any other it prints n as 0 why?
#include <iostream>
using namespace std;
int main() {
int n;
cin>>n;
cout<<n;
return 0;
}

Answer 1

🅰🅹 🅐🅝🅐🅝🅣
You may want to review and revise your answer.
You can assign a char value to an int. int is a chars underlying type and implicit type conversion from char to int can occur. It just doesn't work directly as an input, but this will work fine;
int x = 'x';
cout << x;
Also, an uninitialized int is only set to 0 as a default when it is static or has global scope. This occurs pre-compile. A non-static int within a function will have a garbage value. Again, here it is the input creating the result of 0 for the mismatched type.

Answer 2

SuZu
Because the type is Integer and you can not assign string or char value to integer.
Also an integer has default value 0 so if you enter anything except integer then you will always get 0

Answer 3

You have to declare the variable n with the type of data you want to pass it, otherwise it will return 0. or handle exceptions so that it only denotes entering numbers

Answer 4

Ohh ok Thanks 🅰🅹 🅐🅝🅐🅝🅣

Answer 5

So If I have a code snippet taking n as an input and I want to show "input must be integers" every time user inputs non Integer value
How I supposed to do that? 🅰🅹 🅐🅝🅐🅝🅣
**[nvm got it]**

Answer 6

Alright thanks for explanation ChaoticDawg , yes I tried int x ='x';
cout<<x; it prints ascii value of character which is understandable