Reverse of a string

Question

Write a program to take a string as input and output its reverse.
The given code takes a string as input and converts it into a char array, which contains letters of the string as its elements.
Sample Input:
hello there
Sample Output:
ereht olleh
can any body tell how i can do this ?

Answer 1

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
//your code goes here
int n=arr.length;
String str="";
for(int i=n-1 ; i>-1 ; i--){
str=str+arr[i];
}
System.out.println(str);
}
}

Answer 2

try this code it will works
import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
//your code goes here
for(int i = 0; i < arr.length; i++){
System.out.print(arr[arr.length - i - 1]);
}
}
}

Answer 3

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
//your code goes here
String reverse = "";
for(int i = arr.length - 1; i >= 0; i--){
reverse = reverse + arr[i];
}
System.out.println(reverse);
}
}

Answer 4

import java.util.Scanner;
public class reverse1 {
public static void main(String[] args) {
Scanner scanner= new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
String rev= "";
for(int i=arr.length-1; i>=0;i--)
{
rev+=arr[i];
}
System.out.println(rev);
}
}

Answer 5

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
//your code goes here
for(int i = arr.length-1; i >= 0; --i){
System.out.print(arr[i]);
}
}
}

Answer 6

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
int len = arr.length;
char[] sol = new char[len];
int n = 0;
for(int k = arr.length-1; k>=0;k--){
sol[n] = arr[k];
n++;
}
System.out.println(sol);
}
}

Answer 7

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
String tmp ="";
//your code goes here
int t = arr.length -1 ;
for (int i = t; i>-1;i--){
tmp+= arr[i] ;
}
System.out.println(tmp);
}
}

Answer 8

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
//your code goes here
int n=arr.length;
String str="";
for(int i=n-1 ; i>-1 ; i--){
str=str+arr[i];
}
System.out.println(str);
}
}

Answer 9

It can be solved using two pointer approch...loop from start to end and swap the first pointer at the start of string and the last point at the end of string and increment the start pointer and decement the last pointer.
Idea of the algorithm
Int low = 0;
Int high = arr.length -1;
for ( int I= 0; I < n; I++){
Swap(arr[low], arr[high]);
low++;
high--;
}

Answer 10

//your code goes here
char[] rvsarr = new char [arr.length];
for(int i =0;i<arr.length;i++){
rvsarr[i] = arr[arr.length-i-1];
}
System.out.println(rvsarr);

Answer 11

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
//your code goes here
for( int x = arr.length - 1; x >= 0; x-- ) {
System.out.print(arr[x]);
}
}
}

Answer 12

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
//your code goes here
for(int i=arr.length-1;i>-1;i--){
System.out.println(arr[i]);
}
}
}

Answer 13

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
//your code goes here
for(int i=arr.length-1;i>=0;i--){
System.out.print(arr[i]);
}
}
}

Answer 14

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
//your code goes here
for(int i = arr.length - 1; i >-1 ; i--)
System.out.print(arr[i]);
}
}

Answer 15

Input: hello
Output: olleh

Answer 16

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String text = scanner.nextLine();
char[] arr = text.toCharArray();
char[] c;
//your code goes here
for(int i=arr.length;i>0;i--)
c[]=arr[i];
for(int i=0;i<arr.length;i++)
System.out.print(c[]);
}
}

Answer 17

change char[] c to a String and construct it in the loop.
String str = "";
for(int i = arr.length-1; i >= 0; i--){
str = str + arr[i];
}
System.out.println(str) ;

Answer 18

Pls don't create duplicates..
https://www.sololearn.com/Discuss/2713428/?ref=app

Answer 19

Iterate through the char array in reverse order.

Answer 20

// first, you should initialize your 'c' char array:
char[] c = new char[arr.length];
// then you should acess array items by giving index in square brackets (so, you doesn't need to iterate backwards:'):
for (int i=0; i<arr.length; ++i)
c[i] = arr[arr.length-i-1];
// also in second loop:
System.out.print(c[i]);