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Because it adds one after it does the test. When i gets to 6 it fails the test and the loop stops and i is printed.
i = 1 while i <=5: print(i) i = i + 1 Here, the system stops after i is 5 because any number higher than 5 will not be true in <=5. For example: if i was 6, the command would have no output, since 6 is higher than 5 Edit: 😎_M_😎 Check my comment again.I answered to the second code👍🏻
Hi, that's because you're using this (<=) operator, while loop adds 1 to i every time it validates its condition as True, so when i is 5, while loop is still validating condition (i <= 5) as True, because i is not less than 5 but it is equal to 5 (At this point, i is 5 ), then while loop keeps running its body and executes line of code ( i += 1), adding one to i (now you got 6). After that, while loop stops running because condition (i <= 5 ) is not True anymore. THAT'S WHY WHEN I IS PRINTED, OUTPUT IS 6 AND NOT 5. You understand now?
To stop printing at 5, you would have to change the while loop from while i<=5: i+=1 print(i) to while i<=5: print(i) i+=1
David Ashton, now I understand, thank you very much. While is a conditional operator, and it checks each element for a condition, the number 6 fails the test and the loop stops, but it is printed, which is strange, like why print a number that failed the test.
Because there you are trying to print after adding 1 to i. So till 6 it will get printed. Try doing it like below https://code.sololearn.com/cFj4Zo8yf23n/?ref=app
Remove the =
Oumar abakar Abakar oumar What was the purpose of posting almost two dozen unrelated codes under the guise of helping? There was no point, and its just spam.
U should use i<5 instead of i<=5
i=0 while i<=4: i+=1 print(i) Second method i=0 while i<5: i+=1 print(i)
The loop doesn't stop at 5 because of the order of the commands within the loop. It currently flows like this: Set i value to 0 While i is less than or equal to 5 Add 1 to i Print i So it will print out 1,2,3,4,5,6 before it results in false. If you change the order to print i before adding 1 to it the results would be 0,1,2,3,4,5.
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You have to add i+=1 after the print function.
When i=5 i<=5 will be true and enter into the loop , There it prints 6; Then loop ends.
Thanks for the answer David Ashton i learn something new
Simba I know that, that's why I'm asking. why does the loop stop at the number 6 and not at number 5?
Hacker-KR4636, Simba Yes, I understand, Hacker-KR4636, your explanation is much more extensive and clear. But why in this code the variable i when equal to 5 does not pass the check again and does not print the expected result 6? https://code.sololearn.com/c3ck9wAiR79r/?ref=app
YEAH, VERY EXTENSIVE, BUT THIS ONE DEFEATS IT😂 When we count from 1 to 5, there are 5 numbers, but when we count from 0 to 5, there are 6 [ 0, 1, 2, 3, 4, 5, 6 ] You're getting the same result as your first code. Add this print function at end of your code and you will see that when while loop stops, i stores 6 as its value. (Here's how you can check what i'm saying, execute this program) i = 0 while i <= 5: print(i) i += 1 print(i) (At this point, i is equal to 5, but you need to add this line at end of your code and in that way you can see what's is the real i value after executing while loop) Outputs: 0 (This 0 is printed because you're using print(i) before ( i += 1), and value of i before ( i += 1) it's 0) 1 2 3 4 5 6 (this because when i is equal to 5, while keeps running because i is not less than 5 but so equal to 5) SORRY IF ANSWERS ARE EXTENSIVE I'M JUST TRYING TO HELP U ALL I CAN😃
The reason why 6 is printed is because i is incremented before printing . If you say inside the while loop ....: i = 0 while I<=5: print(i) i+=1 The result will end at 5 for the above piece