Python Problem (Another one)

Question

Bro literally I am doing great and progressing in python. I haven't bought the pro version yet but there is also some free challenges. So like the other challenges there is a challenge about while loop called "While loop changed". And I literally cant solve it. Giving the codes description down below.
You need to change the code to calculate and output the sum of all digits of the input number.
Sample Input
643
Sample Output
13
Explanation
The sum of the digits of 643 is 6+4+3 = 13.
Thats how the question looks like. Man give me the solution as well as the explanation. Thank you for helping me.

Answer 1

Dont worry its quite easy to understand :-
1) First break down the problem . In this case , you have to add the digits of a number which is given as an input
So :- Input--->Add the digits of the input--->print the output
The input and print part isnt really hard ,is it ?
Lets see the adding digits part
Approach -
iterate through the number by converting to a string. ITERATE means seeking each element/portion one by one . Converting to a string , why is it even necessary ? It is because only some data types in python ARE ITERABLE . One such type is a string
So
num = str(input()) #converting to a string
sum = 0 #originally the sum is 0.
for i in num : # This is the iteration , assuming that you know about for loops . If you dont , I suggest you to learn about them.
sum = sum + eval(i)
#Now , after the iterations its time to give the output !
print(sum)
If you still dont understand what I meant , dont worry all of it will become obvious once you learn about for loops.

Answer 2

sum = 0
for digit in str(643):
sum += int(digit)       
print(sum)
Try this, should be self-explanatory.

Answer 3

It is really easy.. but i have to use longer syntax than for in loop..
So i'll help you with the while loop
This is my code:
#in while loop:
inp = input()
sum = 0
d = 0
while d < len(inp):
sum += int(inp[d])
d += 1
print(sum)
#in for in loop:
inp = input()
sum = 0
for d in inp:
sum += int(d)
print(sum)
And that's from me..
Stay confidence and keep typing! :>

Answer 4

Using while loop:
(what we all are taught)
num = 12345
sum = 0
while num:
sum += num % 10
num //= 10
print ( sum )

Answer 5

Ok simply change them into list using list function then iterate it and add them
a = list("12345")
print(eval("+".join(a)))
use this simple logic

Answer 6

In order to get the digits, convert the integer to a string and then sum up the characters as integers with the help of a for-loop.

Answer 7

print(sum(int(ichar for char in input()))
Input a number. Using input() creates a string. Iterate over the string, converting each character to an integer with int(). Use sum() to add them together.
https://code.sololearn.com/cOWCAxOR6Nqa

Answer 8

a b h i n a v had it right with some minor changes necessary for it to pass sololearn's test cases.
Try this:
n = int(input())
length = 0
sum = 0
while n > 0:
sum += (n % 10)
n //= 10
length += 1
print(sum)

Answer 9

Max Harder Can you plz Explain???

Answer 10

I had allready written Umar Haque

Answer 11

丹ⓨㄩک廾 If you explain that to me it would be very helpful

Answer 12

Try:
num=643
digits=str(num)
sum=0
for i in range(len(digits)):
sum=sum+int(digits[i])
print(sum)

Answer 13

@Theo can you please explain that?

Answer 14

丹ⓨㄩک廾 Can you plz write a code for me so I can understand