Shape A

Question

How can I use arrays instead of the sentence on Line 7?
https://code.sololearn.com/coxG3PhfjT8Q/?ref=app

Answer 1

Alaa Z. Abu Zuhair nice try👍
but here are couple things you overlooked in your code :-
1) array index starts from 0 not 1
2) your else statement is inside the second *for* loop and will execute every time the if statement is false. { Just bring it outside}
After applying all the fixes your code should look something like this👇
https://code.sololearn.com/cmGg1DpWYoTU/?ref=app

Answer 2

Fill all those values in an array and then for every iteration just check if that value is in the array of not.

Answer 3

Thanks Arsenic , I tried it but it didn't look right.. I wanted the letter A to appear on the output screen
int main(){
int i,j;
int A[7]={5,9,11,20,26,27,35};
for (i=1;i<=35;++i){
if(i>=14&&i<=18) goto one;
for (j=1;j<=7;++j){
if(A[j]==i)goto one;
else {
cout<<" ";
continue ;
}
}
one:
cout<<"*";
if (i==9||i==20||i==27)continue;
if (i>=14&&i<=17)continue ;
else cout<<"\n";
}
return 0;
}

Answer 4

Ok👍
Thanks , I am grateful to you Arsenic