How does increment work?

Question

a=2,b=6
++a+b++
Explain the Operation

Answer 1

First preincrement will be solve after that post increment
Int a=2,b=6,c;
c=++a+b++;
Here the value of a will be incrementing by 1 becz ++a so the expression will be
c=3+6=9 and 9 will be assign in c variable after evaluation of c variable b value will be increase . Hope u understood if u don't know how pre and post inc/dec working u can watch youtube tutorials.

Answer 2

Use the search bar for searching more answers to your question.
https://www.sololearn.com/discuss/1777199/?ref=app
https://www.sololearn.com/discuss/160327/?ref=app
https://www.sololearn.com/discuss/1047413/?ref=app
https://www.sololearn.com/discuss/138271/?ref=app

Answer 3

a=2
b=6
print(++a + b++) output : 9
why?
Since print(3 + 6)
explaination:
in ++a, "++" comes before "a" so a is incremented first hence when that print statement is executed we have a becomes 3.
in b++, "++" comes after "b" so b is incremented later hence we still have b as 6 when the print statement is executed. (later after the print statement is executed b becomes 7)

Answer 4

ThanksRohit

Answer 5

Can you explain bro Rohit

Answer 6

My example problem how does that workRohit

Answer 7

This was a quiz I gave 9 first it went wrongRohit so I was in confusion and wanted to know the logic