Need someone to check my code. I dont get why I got an indexoutofrange error in my code.

Question

I am trying to write a program that finds the minimum of the 2nd element of a two dimensional array, but I get an indexoutofrange error.
Code below:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace SoloLearn
{
class Program
{
static void Main(string[] args)
{
double[,] cs = { { 1, 10 }, { 2, 9 }, { 3, 8 }, { 4, 7 }, { 5, 6 }, { 6, 5 }, { 7, 6 }, { 8, 7 }, { 9, 8 }, { 10, 9 }, { 11, 10 }, { 12, 11 } };
// Determine min first
double minimums = 9999;
for (int i = 0; i <= cs.Length; i++)
{
if (cs[0, i] < minimums)
{
minimums = cs[0, i];
}
else
{
}
}
Console.WriteLine(minimums);
Console.ReadLine();
}
}
}

Answer 1

I made such a stupid mistake. Thank you very much for the patience.

Answer 2

It seems that the location of the variable location_of_min matters. The computer said it didn't exist in the current context because it was declare inside the first for loop.
@Rithea Thanks again.

Answer 3

Tried that but didn't work. Visual studio is pointing to this line
if (cs[0, i] < minimums)
Im not sure whats wrong with it.

Answer 4

Francis change the line to "if(cs[0][i] < minimums" and see if it works

Answer 5

I created a two dimensional array (2 rows and 2 columns). I want to find the lowest number among the 2nd column ( referring to the 10,9,8,7,6,5, and so on). The answer is suppose to be 5.
I realized cs.Length is wrong because it counts all the elements so it returns 24.

Answer 6

Here I changed my code just so we can keep our mind of length of the index. There are 5 rows, but I set the condition to i<3 (i=0) which means it will not perform the 5th statement on the row. However, I still get the same error.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace SoloLearn
{
class Program
{
static void Main(string[] args)
{
double[,] cs = { { 1, 8 }, { 2, 5 }, { 3, 2 }, { 4, 4 }, { 5, 9 }};
// Determine min first
double minimums = 9999;
for (int i = 0; i <3; i++)
{
if (cs[0, i] < minimums)
{
minimums = cs[0, i];
}
else
{
}
}
Console.WriteLine(minimums);
Console.ReadLine();
}
}
}

Answer 7

After finding the minimum, I want to find the maximum, but not the maximum on the second column(not the minimum between 3,5,6,2,5,3), just the maximum between the first number until the location of the minimum(minimum between 3,5,6,2) on the second column. The maximum is suppose to be 6.
It works if I use this.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace SoloLearn
{
class Program
{
static void Main(string[] args)
{
double[,]list = { {0,3}, {1,5}, {2,6}, {3,2}, {4,5}, {5,3}};
double current_min= 9999;
for (int i = 0; i < (list.Length/2); i++)
{
if (list[i, 1] < current_min)
{
current_min = list[i, 1];
int location_of_min = i;
}
}
double max_before_current_min = -1;
for (int j = 0; j < 3; j++)
{
if (list[j, 1] > max_before_current_min)
{
max_before_current_min = list[j, 1];
}
}
Console.WriteLine(current_min);
Console.WriteLine(max_before_current_min);
}
}
}
However, lets say I don't know where the location of the minimum is.
Instead of using for (int j = 0; j < 3; j++),
I will use this (int j = 0; j < location_of_min; j++).
When I use the latter, it says location_of_min doesn't exist in the current context. How do I do it?

Answer 8

I changed {1,8} to {1,2}.
Answer should be minimum is 2 and maximum is 5, but it returned 2 and 2.

Answer 9

Pls wat editor 4 html