Opening file from variable(C)

Question

https://code.sololearn.com/c2kD6uHq15kU/#c
I have to open 26 files based on the input of the first file:
the first file is series of 3 letters strings like
ABC
DEF etc.
i have to open the files ABC.txt, DEF.txt... and im trying to do it with sprintf but it gives me an output i dont understand.

Answer 1

There are several problems:
* The char pointers are uninitialized.
* The call to fgets would return only 2 bytes, not 3.
* Files are not getting closed

Solutions:
The char pointers need to be char arrays so that there is memory available to store the strings.
char*xyz; //should be: char xyz[4];
char*ilfile; //should be: char ilfile[8];

In the call to fgets() the second argument (parameter n) should be changed from 3 to 4 in order to read 3 bytes. Calling fgets() reads n-1 bytes from the file and then it always adds a null as the nth byte.

Remember to close each file that you open. You should have fclose(aprixyz); within the while loop.

Answer 2

fopen does not work on sololearn.

The playground is a remote server and cannot find the files on your computer.

fgets does not work because is empty
sommario

Answer 3

I'm working on my computer, i just posted the code here to show it

Answer 4

And sommario is the txt file that i described in the description

Answer 5

Ok. Was not aware of that