Please help, why 10?

Question

#define prod(i, j) i * j
int main() {
int x = 3, y = 4;
print("%d", prod(x + 2, y - 1));
return 0;
}

Answer 1

Here operation in printf() executed as:
prod(x+2,y-1)
prod(3+2*4-1)
prod(3+8-1)
prod(3+7)
prod(10)
In this way output is 10

Answer 2

The Crazy Programmer Thank you
Wow, I didn't see that coming

Answer 3

prod(x + 2, y - 1) = prod(3 + 2, 4 - 1) = 3 + 2*4 - 1 = 3 + 8 - 1 = 10

Answer 4

Note that the behavior of the prod(i, j) may not be as expected, to fix this, maybe you can state:
#define prod(i, j) (i)*(j)
This example shows that the define should be used very carefully.

Answer 5

It happens because multiplication has higher precedence than sum. It is often tricky using preprocessor functions