Can you explain me that why the output is -11?

Question

#include<stdio.h>
int main()
{
unsigned int var = 10;
printf("%d", ~var);
return 0;
}

Answer 1

Thank you now I understand

Answer 2

Can someone explain this a bit more clear, please

Answer 3

Can someone explain this a bit more clear, please

Answer 4

Above code gives -11 as output of printf.
var is type of unsigned int,
var is assigned with 10,
operator ~var converts var to complement of 10.
printf %d coverts it to integer while printing it's representation makes it -11
in 32 bit binary representation
10 => 0x0000000A
-11 => 0xFFFFFFF5
in C language int is represented as 2's complement.
That results in to print -11.
var contains after complement in 32 bits as
0xFFFFFFF5
2's complement of above is
0x0000000B
it is 11 in decimal representation
That's why print with format %d prints -11 in output.