Help with code to remove duplicate in a string and return tuple of the remaining word and number of word removed python
- 'remove' is a method of list objects, not strings, and get an argument to remove from the list on wich the method is applied. - 'set' return a set of unique elements ( remove dupicates ) from a list. Passing a string instead a list is possible, but will split the string in an array of character, so the result of 'set(string)' is not an array of words... Instead of implicitly auto-split your string in an array of characters, split it explicitly withs spaces: words = string.split(" ") ... you maybe must do some treatment to trim words of punctuation, spaces remainig ( empty items in list if many successives spaces in the string ). Then use the set() function on the 'words' list, give you the list of unique words: unique_words = set(words) Now, you need to implement the counting of words, remove those wich have a count greater than one, and get the count of thoses removed ( according to your needs, can be the count of unique words removed, or the count of words removed in original string... ). For that, initialize a count variable to zero before removing words, and each time you remove a word, increment your counter... Anyway, did your problem suppose that there is necessarly once unique word supposed to be remaining? If not, you should think to return a tupple with a list of word and the removed word count insread of just a tupple word/count.
Show your code for getting help ^^
Remove = string. remove If len(set (string))! = len(string) return (Remove, len(Remove))
def remove_duplicates(string): s = list(string) t = set(s) final = len(string) - len(t) return "".join(t), final print(remove_duplicates("aaabbbac")) >>('acb', 5)