How to get response of radio button (if it is checked or not) and store it into mysql database using node js? | Sololearn: Learn to code for FREE!

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How to get response of radio button (if it is checked or not) and store it into mysql database using node js?

Webdevelopment

3/11/2020 8:42:07 PM

R_N

10 Answers

New Answer

+4

R_Chandra Have you written your submit file where you will send data to store in database? Check link to understand:- https://www.sitepoint.com/forms-file-uploads-security-node-express/ https://programmingmentor.com/post/save-form-nodejs-mongodb/ “Using Node.js & Express.js to save data to MongoDB Database” by Jennifer Bland https://link.medium.com/X7nsXNzVM4

+3

R_Chandra I just created a webpage run with node.js, the webpage displays simple multiple choice for submission to node.js, store on sqllite. Check out the webpage and source codes. https://code.sololearn.com/WAKK667qwYa5/?ref=app https://github.com/cv2k10/radio-choices-node-submission Go through the codes to find your solution, ask me if any of the source code you don't understand.

+2

You have already asked this question. https://www.sololearn.com/Discuss/2196138/?ref=app

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R_Chandra How we can know without proper information. Share your code so anybody can see.

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app.post("/submit",function(req, res) { console.log(req.body) res.render('index',{title:'data saved', message :'data saved successfully '}) }) here index is my pug file and submit is id of submit button.

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R_Chandra here /submit means action where your request will go. It's not a id.

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Removed "/" still getting "cannot POST /submit "

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I have only one html file (front.htm) having radio button and submit button

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Get method is not working

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Calvin Why two script is written in index.html file.? I've not used script tag in my html file. Is it necessary?