Why is False**False = 1?

(n^y) /(n^y) = (n/n) ^(y-y) => (n/n)^(0)=> 1, at school in math we learn that if n=0, 0^0 is indefined

False is convertible to 0. Whatever int ** 0 == 1.

No it's 1 in math too

Long story here: https://en.m.wikipedia.org/wiki/Zero_to_the_power_of_zero tl,dr: One of these things in maths we just agree upon - or not. 😉 Anyway: Python follows this rule, so that's how that challenge gets to its result.

The number is true, so it is 2**0, in math 0 degree of the number is 1

I think, i got it now... thanks to all...

Okay... thats true in math with any numbers except 0, but i still dont get it why 0**0 = 1 in python... in math 0**0 = 0