Ascending order without conditions

Question

Sort the list in ascending order without using conditions

Answer 1

list.sort()
It doesn't have conditions and list will be sorted.

Answer 2

With logically

Answer 3

Sorting manually

Answer 4

So you mean manually without using inbuilt functions?

Answer 5

https://code.sololearn.com/c94LoiaLgeOH/?ref=app
I hope this helps you.
With this code you can sort a list without using any inbuilt function.

Answer 6

Yes, that's right

Answer 7

Also I need program of registration form, to clear an interview so please help with code and explanation, it will be helpful

Answer 8

I need explanation for above ascending order code, if u don't mind..

Answer 9

a=[1,3,5,4,7,2,3]
def check(a):
for i in range(len(a)-1):
if a[i]>a[i+1]:
return False
while check(a) == False:
for i in range(len(a)-1):
if a[i]>a[i+1]:
a[i],a[i+1]=a[i+1],a[i]
print(a)
What this code does is that we have defined a function to check whether the list is sorted or not. How does this function check it? It's simple. In a sorted list the element that comes before is either smaller or equal. This function returns False if that is not the case with the list. Now combined with this function is a while loop, which checks the condition. The while loop will continue until the condition become true which if only possible when list is sorted, so it willl execute until the list is sorted. Here comes the main part... The for loop will check the two elements and compare them. If a larger number comes before the smaller one, those two are swapped. It is continued until the whole is list is sorted. And Finally the list is sorted! Hope you understood.

Answer 10

MD Thoùfèék Thoufi If you still didn't understand, I can explain it more briefly by messaging you if you want.

Answer 11

For more details-
https://www.sololearn.com/learn/774/?ref=app