Help solve the problem

Question

How to solve the problem? Here is the task:
You run a hovercraft factory. Your factory makes ten hovercrafts in a month. Given the number of customers you got that month, did you make a profit? It costs you 2,000,000 to build a hovercraft, and you are selling them for 3,000,000. You also pay 1,000,000 each month for insurance.
Task:
Determine whether or not you made a profit based on how many of the ten hovercrafts you were able to sell that month.
Input Format:
An integer that represents the sales that you made that month.
Output Format:
A string that says 'Profit', 'Loss', or 'Broke Even'.
Sample Input:
5
Sample Output:
Loss
Entering 10 displays an error. Please indicate the error in the code.
sales = int(input())
balance = int(sales*1000000-1000000)
if balance > 0:
print('Profit')
elif balance == 0:
print('Broke Even')
else:
print('Loss')

Answer 1

Ah, I thought insurance didn’t apply to ships. Thanks you

Answer 2

Hare is solution of your problem
order= int(input())
sales=order*3000000
cost=20000000
balance = int(sales-21000000)
if balance > 0:
print('Profit')
elif balance == 0:
print('Broke Even')
else:
print('Loss')

Answer 3

Sorry if I wrong said about problem

Answer 4

Vlad The code is wrong.
If I sold 2 hovercrafts in the month:
Earn: 6M:
Selling 2 hovercrafts (2*3M=6M)
Loss: 28M:
Creating 10 hovercrafts (10*2M=20M)
Insurance of 8 hovercrafts (8*M=8M)
6M - 28M = -22M (loss)
In your code it would be:
sales = 2
balance = sales * M - M = 2M - M = +M (profit)

Answer 5

yo Vlad this is the code I wrote with explanations
you can run it and see, it works but just go through why it works, dont want to just solve it for you without helping
#just assigning a variable to 21 million, this is the amount spent on making 10 hovercrafts in a month
#this is usefull in later calculations
per_month_payments = 21000000
#getting input of how many hovercrafts were sold
hovercrafts_sold_month = int(input("How many hovercrafts were sold? "))
print(hovercrafts_sold_month)
#getting the amount of money I- the company made
cash_made_from_HCs = hovercrafts_sold_month * 3000000
#cashiness is used in calculating if I- we the company made a profit a loss or if it was Broke e- Even
cashiness = cash_made_from_HCs - per_month_payments
if hovercrafts_sold_month <= 10:
if cashiness > 0:
print("Profit")
elif cashiness == 0:
print("Broke Even")
elif cashiness < 0:
print("Loss")
else:
print("how would I- The company sell more hovercrafts then I made??? Sorry didn't mean I made, I meant WE made")

Answer 6

#FROM PYTHON
sale=int(input())
Cp=2*10+1
Sp=3*sale
if Cp>Sp:
print("Loss")
if Cp<Sp:
print("Profit")
if Cp==Sp:
print("Broke Even")

Answer 7

#python
kater = int(input()) #кількість проданих катерів
min = 21000000
"""min - це загальна кількість вират: на виготовлення (10*2млн) і страховку (1млн)"""
katers = kater*3000000
"""прибуток з продажу"""
profit = katers - min #обчислення загального прибутку
if profit == 0:
print ("Broke Even") #якщо витрати=прибутку
elif profit > 0:
print ("Profit") #якщо прибуток>витрат
else:
print ("Loss") #якщо прибуток<вират

Answer 8

n = int(input())
if n > 7:
print("Profit")
elif n < 7 :
print("Loss")
else :
print("Broke Even")

Answer 9

Seems to be a logic error.

Answer 10

i translated incorrectly. In test with in input 7 programm output profit. But this is a wrong answer. Is it a mistake in the task or mine in code? Code work good.

Answer 11

I did mine using C++ but its not working
#include <iostream>
using namespace std;
int main()
{
int sales;
double S_P=3000000, Insurance=1000000,C_P=2000000,Amount_received;
const int Num=10;
double principal_amount=(C_P*Num)+Insurance;
cout<<"Enter the number of customers: ";
cin>>sales;
Amount_received=(sales*S_P);
if(Amount_received<principal_amount)
{
cout<<"Loss";
}
if(Amount_received>principal_amount)
{
cout<<"Profit";
}
if(Amount_received==principal_amount)
{
cout<<"Broken Even";
}
return 0;
}

Answer 12

Я не знаю как у меня это сработало, но это работает :/
C++
#include <iostream>
using namespace std;
int main() {
int N = 0;
cin >> N;
if (N < 7){
cout << "Loss";
}
else if (N >= 8){
cout << "Profit";
}
else if (N <= 7){
cout << "Broke Even";
}
return 0;
}

Answer 13

Very Simple Way To Solve!
import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int sales = sc.nextInt();
if (sales<5 && sales>=0) {
System.out.println("Loss");
}else if (sales==7){
System.out.println("Broke Even");
}else if (sales>7 && sales<=10){
System.out.println("Profit");
}
}
}