Answer 1

Sankalp👨‍💻👨‍💻
I will give you a tip:

Take input as a String using nextLine(). Use split(" ") method which returns a String array.

E.g. "Hello World"
-> [Hello, World]

Then it should be much easier.

Answer 2

Jayakrishna punctuation does not count.

Answer 3

Denise Roßberg ok. I understood that..
In 1, reply, When I posting 1 or 2 words I missed to mention, after posting I edited that.. You may read it before that...
OK. He just missing char count only.. Let us see, can he do it...

Answer 4

Sankalp👨‍💻👨‍💻
Math.ceil () + count only letters = solution.

Edit: You can believe us. We have already solved this challenge. ;)

Answer 5

Sankalp👨‍💻👨‍💻
I am a bot confused about
input -> XX:XX XX
Maybe you confused the challenges. Looks like military time.

But concrats that you solved it.

Answer 6

why you are adding space by n=" " +n.
And use ceil function.
There mentioned to round up...

Answer 7

Sankalp👨‍💻👨‍💻 No need to add space. If you add you will get extra word count...
And use ceil function...

Answer 8

Sankalp👨‍💻👨‍💻

Using Math.ceil() is correct.

Read the description and look at the testcase 1.
"You have to remove all punctuation".
Testcase 1 contains "?".
That's why your code fails.

Answer 9

Sankalp👨‍💻👨‍💻 Yes. I missed that one more, with that your code by char++, the punctuation marks also counts so you need calculate only charecters ..

Answer 10

Denise Roßberg see his code... He is calculating all chars other than space...
Iam also telling the same...
I already solved it at the time of challenge...

Answer 11

Sankalp👨‍💻👨‍💻 Its simple...
1. Count chars without punctuations...
2. Count words
Find avg by ceil function...
I think it's better to, i give code.. Only you missing char count...
Can you try one more time for char count..

Answer 12

Jayakrishna Sankalp👨‍💻👨‍💻

"Takes in a string, figure out the average length of all the words and return a number representing the average length. Remove all punctuation. Round up to the nearest whole number."

Remove all punctuation!

Case 1:
Can you do that?

can 3
you 3
do 2
that 4
-> 12 / 4 = 3
3.0 rounded up = 3

Case 2:
The longest word in the dictionary is...

the 3
longest 7
word 4
in 2
the 3
dictionary 10
is 2
-> 31 / 7 = 4.43
rounded up: 5

Answer 13

Sankalp👨‍💻👨‍💻 Round gives
4.42 to 4.0
4.78 to 5.0
Simply Belove 0.5 to 0.0 and above 0.5 to 1.0
ceil results both to 5.0 i.e(4.4, 4.7)

Answer 14

Sankalp👨‍💻👨‍💻
ceil() rounds always up.
3.0 -> 3.0
3.1 - 3.9 -> 4.0

round()
2.0 - 2.4 -> 2
2.5 - 2.9 -> 3

Answer 15

Jayakrishna
I misunderstood you earlier. I thought you meant in the challenge you have to count punctuation marks. Instead, you meant that his code did it.
Yes, I noticed that.

I think we're done here. I don't know what else to mention.

Answer 16

Can you try it? Or can I give solution?

Answer 17

Sankalp👨‍💻👨‍💻
OK. I already mentioned that you missing in charecter count. Use ceil function.
Look for those...

Answer 18

Sankalp👨‍💻👨‍💻 Just focus on description, not on the test cases...

Answer 19

Sankalp👨‍💻👨‍💻 we also prefer to solve by own.. So that's why I asked to try.. try... Just reminding what you missing.. We just want to know also what is your preference...
But it seems that you are not picking the logic..
I faced that situation lot of times.. If I struck, and came back in other day to solve, it's better that to reset code and write again from the start...
So do like this..
Try.. Try.. Again.. If need help then ask...

Answer 20

ndhdkdid