 Skee-ball from Code Coach | SoloLearn: Learn to code for FREE!

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# Skee-ball from Code Coach

Result is error for test 3. What wrong? https://code.sololearn.com/cJJj828SQ8rv/?ref=app

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Russ It is ok, but why If a//(b*12)>0: ... Don,t work? My be you have a link of article about so type and examples? (length of types)

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a / 12 >= b is enough. You not need math.trunc()

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x=int(input()) y=int(input()) if ((x/12)>=y): print("Buy it!") else: print("Try again") I code that, and it solves

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Petr I am not sure but your code does not work for costs = 0.

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Russ Denise Roßberg I think problem is solve. Thank you.

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Petr yes, it's possible Denise Roßberg nailed it there - very good point.

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Petr here is an alternative points = int(input()) cost = int(input()) import math tickets = math.floor(points/12) if tickets >= cost: print('Buy it!') else: print('Try again')

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Russ I try many variants,f.e.: a//12//b>0, round, other functions of math, but always result is false for test 3. I can not see task for this variant. I try to do this second day...

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Russ a=int(input()) b=int(input()) if a-12*b>0: print("Buy it!") else: print("Try again") Not work

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Denise Roßberg It is only one variant from many other. I mean trunc()...

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Russ I used early variant b==0, and includid it in add if. But it is not change the result

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Russ Denise Roßberg Thank you . I get 5 ok. But i do not like it, couse i don,t understand why my early codes are not right

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Has some problems with round(float) in python. If you take round(0.5) it will return 0, round(2.5) return 2. But round(1.5) return 2

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Hmm, seems like it *should* work. Maybe it comes down to a rounding error. See if you can modify it to work without dividing.

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Petr Like I said, try to do *without* dividing.

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Petr Why does it need to be strictly greater than 0?

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Petr And I mean if a / 12 >= b: //print else: //print works for all cases.

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Ok so you have it now. What I was trying to get you to do was: if a-12*b>=0:... the ">=" was the sticking point that you'd missed. I'm not sure why your original code failed, as I said earlier. I can only assume that case had the *exact* number of points necessary to get the prize, and somehow a rounding error wheb dividing worked its way in. I couldn't find an example to demonstrate it though. (a/12)//b>0 would fail, whereas (a/12)>=b would work.

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Sorry - misread. Again, not sure, sorry.