Can you explain the following code, it reverses a no but I don’t know how it works?

Question

n=12345
rev=0
while(n>0):
dig=n%10
rev=rev*10+dig
n=n//10
print("Reverse of the number:",rev)

Answer 1

it takes the left digit using reminder operator
then multiple it with 10 to add the next digit at the right
usually I understand codes by printing the changes
check this may help
https://code.sololearn.com/c6Tgr225h1Ea/?ref=app

Answer 2

welcome

Answer 3

thank you both of you for your support , I am new to coding , your help really counts
~ swim ~ thank you , I didn’t downvoted your answer intentionaly may be it was something in haste though I realised my mistake now . I would look forward for your help in future