Confused in pointers with arrays

Question

Let there is 1-D array arr={1,2,3,4,5,6}
And 2-D array A={10,11,12,13,14,15}

Now the real problem..

cout<<*arr // 1
cout<<*A // address
cout<<**A // 10

Can you explain why the output is like this??
In 2d array A points to the first element then writing *A should print first elememt like 1D array does..

Answer 1

Martin Taylor
Yeah..I gave an overview about my problem..bcoz i wanted explanation of cout statements only..so there was no need of whole code..

Anyway, thanks for explaining😊

PS:- Why did you think that both are single dimensional array??🤔 2D array can be declared like this..

Answer 2

Martin Taylor

I already mentioned there was no need of code in this..I just wanted to know the concept of array with pointers..
and I also wrote “let there is an 1D/2D array" (just suppose there is an array)

Anyways, Sorry if it bothered you to understand the problem..