Fill in the blanks to define a function ''myFunc'', which throws an exception if its parameter is less than 0. void myFunc(int a | Sololearn: Learn to code for FREE!

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Fill in the blanks to define a function ''myFunc'', which throws an exception if its parameter is less than 0. void myFunc(int a

ho do work out this

1/29/2017 6:15:06 PM

marvellous gwenzi

17 Answers

New Answer

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Ans: void myFunc(int arg) throws IllegalArgumentException { if(arg <0) throw newIllegalArgumentException(); }

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public void do(int x) throws IOException { if(x<0) { throw new IOException(); } }

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throws if 0 new

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if (a < 0) throw new IllegalArgumentExcpetion("Parameter cannot be negative");

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public viid(int x); throws IOException{ if(x<0) { throw new IOException(); } }

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public void do(int x){ try IOException{ if(x<0){ throws new IOException } } }

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Fill in the blanks to handle all possible exceptions.

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Fill in the blanks to declare a method that takes one argument of type int. public int myFunc( x) return x*10; I need help

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Drag and drop from the options below to create a method that throws an IOException if the parameter is negative. Answer :- public void do(int x) throws IOException { if(x<0) { throw new IOException(); } }

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public void myFunct(int arg) throws IllegalArgumentException { if(arg<0) { throw new IllegalArgumentException(); } }

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answers in order: throws IOException throw new

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throws if 0 new

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throws IOException throw new

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throws if 0 new

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Drag and drop from the options below to create a method that throws an IOException if the parameter is negative ANS:public void do(int x) throws IOException { if(x<0) { throw new IOException(); } }

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public void do(int x) throws IOException { if(x<0) { throw new IOException(); } }