elif statement issue

Question

Hi all, I m new to python. I was just tried the following code for my practice but it seems I m geeting wrong answer. Please let me know where I’m making mistake.
>>> a=input(“Enter a number between 1 to 4: “)
Enter a number between 1 to 4: 2
>>> if a==1:
Print(“Entered number is 1”)
elif a==2:
Print (“Entered number is 2”)
elif a==3:
Print (“Entered number is 3”)
else:
Print(“Entered number is 4”)
Output :
Entered number is 4
How?? I entered 2

Answer 1

This is a very common issue that happens frequently. If you use input() function and enter something, this will always be stored as string. So in your case input may be 2 but it‘s stored as ‘2’. So you either have to compare it as strings like :
if a == ‘2’
or you convert input instanty to int as Jay Matthews mentioned.

Answer 2

Thanks Jay, it works. But if I didn’t define it as a integer, then by default will it take as a string??

Answer 3

Thanks.