U can definitely not use 1. It is out of our options.
Now, u must know that this is stored as an array of characters, with proper index numbers, I. E, R has index number 0, o has index number 1 and so on. So, I guess u know why 1 is out.
Now, u can use -0. Then the loop will be like (assuming n is the index of the last letter, before the null character (\0))
for(; n >= -0; n--) cout myName [n];
Because the first character has index 0.
For using -1, everything will be same except the condition. It would be, clearly enough, n > -1.
Try to run this.
I hope it helps 😊😊