javascript

Answer is arr1, '...', 4

answer is arr1 ... 4

let a = [1,2]; let b = [3,4]; let c = [...a, ...b]; console.log(c) //outputs [1,2,3,4] There would be not third param in c

Arr1 is defined as 1,2,3 and arr2 is defined is 5,6,7,8 It’s supposed to read 1,2,3,4 and so on. Starting the clause you have to write...and the arr sequence in this case arr1. The next section is easy as it’s just the number 4 because if you look at it 4 is still missing between arr1 and arr2.

answer is 4

const arr1 = [1, 2, 3]; const arr2 = [5, 6, 7, 8]; let arr3 = [...arr1, 4, ...arr2];

Ok it's 4 but what's before arr1 pls help me

answer is : arr1 ...arr1 4

const arr1 = [1, 2, 3]; const arr2 = [5, 6, 7, 8]; let arr3 = [ ... arr1, 4 , ...arr2];

the Answer is arr1, '...', 4

Fill in blanks to make the variable arr3 look like the following: [1, 2, 3, 4, 5, 6, 7, 8]. const arr1 = [1, 2, 3]; const arr2 = [5, 6, 7, 8]; let arr3 = [ ... arr1, 4, ...arr2];

What [... arr1, ...arr2];

answer is arr1 [] and 4

Answer is const arr1 = [1, 2, 3]; const arr2 = [5, 6, 7, 8]; let arr3 = [...arr1, 4, ...arr2];