Why when compare NaN it return always false ?

Question

var n1 = 5 * "hossam";
var n2 = 5 * "hossam";
console.log(n1 === n2); //false
console.log(n1 == n2); // false
Why ???

Answer 1

In terms of accepting NaN != NaN, something which is not a number is not necessarily equivalent to something else which also isn't a number. All in all, like Jomari pointed out, NaN is just designed to fail the equality test since NaN does not refer to anything specific.

Answer 2

n1 and n2 produce NaN
as because you multiple it with not a number value(NaN)

NaN is supposed to denote the result of a nonsensical computation, and as such, it isn’t equal to the result of any other nonsensical computations.

NaN is only one value in JavaScript that is not equal to itself!!

Answer 3

That's just the way how it was configured. NaN will fail every equality check to any value including to itself.

Answer 4

I won't use it for compare but all what I want know is what behind seen ? ... for ex: int x = new Int(5);
Int y = new Int(5);
Both not equal coz different in memory address ... etc