Python operator precedence

Question

So I tried in the playground and got this:
print((True == False) or True) and the output is True.
As I see it, this statement equals this:
print(False or True) and the output is True.
Does this mean True has a higher precedence than False? If not, what’s the explanation?
Also are “print((True == False) or True)” and “print(True == False or True)” the same since == has a higher precedence than or?
Thanks in advance!

Answer 1

True is not operator! "True == False or True" is equal to "(True == False) or True" because == has higher precedence than or. True or False do not change the precedence of operators