JavaScript parseInt

Question

function convertToInteger(str) {
parseInt(str);
return parseInt;
}
convertToInteger("56");
I need to parse any number that enters the function. Please where i'm I wrong?

Answer 1

it should be...
function convertToInt(n)
{
return parseInt(n);
}

Answer 2

parseInt is a funcion, a function returns a value, and if u want tô return this value, you should to assign this function call to a var, for example: var prs = parseInt("3");
return prs;
In your function, you returned parseInt func, not this return for "56" :p, I'm BR but.. I hope that u be able to understand ;w; srry

Answer 3

hello there.
In your exemple you did return the parseInt function. You need return just value instead. Note:
var str = '56';
var decimalNum = parseInt(str, 10);
The ten number force decimal number.

Answer 4

Thank you friends 👊