Inserting path to open file | Sololearn: Learn to code for FREE!
New course! Every coder should learn Generative AI!
Try a free lesson
0

Inserting path to open file

Here is my code #include <string> #include <fstream> using namespace std; string Path = "D:\\DevPrograms\\Test"; //This a the folder containing a test.txt file int main (){ ofstream File; File.open ("What should I enter here to use the Path var above, and then add file name 'test.txt' to open it") }

2nd Aug 2018, 5:04 PM
Jordan
Jordan  - avatar
2 Answers
+ 2
That is sort of what I have currently. path = "D:\\ DevPrograms\\Test\\test.txt" and it works The problem is you have to have a var for each file to define a certain path. Thus is there a way to select a folder with a bunch of files in it, and then select a certain file when you go to open it. For example: Path = D:\\... file1.open ((Path+"Test1.txt")) file2.open ((Path+"Test2.txt")) Edit: I figured it out. string Path = D:\\DevPrograms\\Test; int main () { fstream File1; fstream File2; File1.open((Path + "\\Test1.txt")) File2.open((Path + "\\Test2.txt")) }
2nd Aug 2018, 7:37 PM
Jordan
Jordan  - avatar
0
Try File.open("D:\\DevPrograms\\Test.txt")
2nd Aug 2018, 6:34 PM
B K