Answer 1

https://code.sololearn.com/W194YYBWreLI/?ref=app

Answer 2

https://code.sololearn.com/csFI4mXJaFWc/?ref=app
https://code.sololearn.com/cNn10rmtfMQn/?ref=app

Answer 3

https://code.sololearn.com/cVrn8XvBATA5/?ref=app

Answer 4

nice

Answer 5

Python oneliner:
https://code.sololearn.com/cUK70VYzHROm/?ref=app

Answer 6

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner sc=new Scanner (System.in);
double a=sc.nextDouble();
double b=a-(Math.floor(a));
if(b!=0.0){
System.out.println(""+a+"is a double value");
}
else {
System.out.println(""+a+"is an integer value"+((int)(Math.floor(a))));
}
}
}
it's my try

Answer 7

Ruby
https://code.sololearn.com/cjQa2CKbM2VU/#rb

C++
https://code.sololearn.com/c3bJ1Wb45sbO/#cpp

Answer 8

# Python
# number given as n

integ, dec = tuple(str(n).split("."))
result = "integer" if all(i == "0" for i in dec) else "decimal"
print(result)

Answer 9

https://code.sololearn.com/w31bSJgzHUz0/?ref=app

Answer 10

@nitish kumar jha - Comparing floating point values to absolute numbers (such as 0.0) isn't a good plan.

Some references:
Very technical - https://docs.oracle.com/cd/E19957-01/806-3568/ncg_goldberg.html
More accessable - http://www.floating-point-gui.de/errors/comparison/

Here's my C solution. Instead of dealing with floating point comparisons, I convert the characters after the decimal point to an integer and compare that to zero. This solution won't work if the decimal point is not proceeded with a valid number (such as ".0232").

https://code.sololearn.com/c902hiAmNjBE

Answer 11

My solution as pythoneliner:
https://code.sololearn.com/ca69PqsUzqT3/?ref=app
https://code.sololearn.com/cBbw6N6jOP70/?ref=app

Answer 12

x.is_integer()

Answer 13

C# shortest answer possible (I think)
60 Bytes
namespace a{class b{static bool c(float d){return d%1f==0}}}

EDIT: -1 byte due to 1f instead of 1.0
EDIT 2: yes, I like codegolf