I dealt with each element of the list using the loop... But I want my new elements to substitute the whole list when I try print(list). How can I get that done?

Answer 1

list_1 = [1,2,3]
for i in list_1:
if i != 4:
value_index = list_1.index(i)
list_1[value_index] = 4
print(list_1)
@ayomide - i am not 100℅ sure about ur requirement, the above code goes through the list elements, if each element satisfies condition, new element substitutes the old one. if this is not your requirement can u be more specific??

Answer 2

@raja- thank you, it dealt with it but it was in three lines of output and all the elements became 4. Now examine the code:
list_1=[1,2,3]
for i in list_1:
print(i+1)
Now every element increases by 1(2,3,4). now when I write: print(list_1) I want my output to be [2,3,4] how do I do that?

Answer 3

@ayomide - print elements out side of loop.
list_1=[1,2,3]
for I in list_1:
list_2 = I + 1
print(list_2)
this will deal with only increment elements in list. but if u wanna substitute specific code , the code in my first works. you have to print out side of loop that's it.